Besoin d'aide svvppppppppp pour demain urgent!!! 1) soit f(x) = (2x + 1) au carre - x (1 - x ) a) développer et réduire f(x) b) calculer f(x) pour x = 1/3 2) so

1/
a)
(2x + 1) ² - x (1 - x )
4x²+4x+1 -x+x²
5x²+3x+1

b)
(2x + 1) ² - x (1 - x )
(2(1/3) +1)² - 1/3(1-1/3)
(2/3+1)² -1/3( 3/3-1/3)
(2/3+3/3)² -1/3(2/3)
(5/3)² -2/9
25/9 -2/9
23/9

2/
a
 (3x - 4)² -25
(3x-4)² -5²
(3x-4-5)(3x-4+5)
(3x-9)(3x+1)
3(x-3)(3x+1)

b)
(3x-9)(3x+1) =0

3x-9 = 0             3x+1 =0
3x = 9                     3x = -1
x = 9/3 = 3                x =  -1/3

c)
(3x - 4)² -25 = 11
(3x-4)² -25 -11 =0
(3x-4)² -36 = 0
(3x-4)² -6² =0
(3x-4-6)(3x-4+6) =0
(3x-10)(3x+2) = 0


3x-10 = 0               3x+2 =0
3x =10                       3x = -2
x = 10/3                       x = -2/3

d) (3 (4/3) -4)² -25 =0
(12/3 -4)² -25 =0
(4-4)² -25 =0
0² -25
-25