Mathématiques

Question

Calcule d'équations :
1) 2(z+3)=5
2) 2-(2z-1)=z
3) 2-2y-1=y
4) 2-2y-1=y
Merci d'avance

1 Réponse

  • 1) 2(z+3)=5
    2z+6 = 5
    2z = 5-6
    2z = -1
    z = -1/2

    2) 2-(2z-1)=z
    2-2z+1 =z
    -2z-z +3 =0
    -3z = -3
    z = -3/-3
    z =1

    3) 2-2y-1=y
    2-2y -1 -y =0
    -3y+1 =0
    -3y = -1
    y = -1/-3
    y = 1/3

    4) 2-2y-1=y
    meme que la 3

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