f(x)=5x²-4x+11 CALCULER f(4-√7/3)

Bonjour Karl58

[tex]f(x)=5x^2-4x+11\\\\f(4-\dfrac{\sqrt{7}}{3})=5(4-\dfrac{\sqrt{7}}{3})^2-4(4-\dfrac{\sqrt{7}}{3})+11\\\\f(4-\dfrac{\sqrt{7}}{3})=5(16-\dfrac{8\sqrt{7}}{3}+\dfrac{7}{9})-16+\dfrac{4\sqrt{7}}{3}+11\\\\f(4-\dfrac{\sqrt{7}}{3})=80-\dfrac{40\sqrt{7}}{3}+\dfrac{35}{9}-5+\dfrac{4\sqrt{7}}{3}\\\\f(4-\dfrac{\sqrt{7}}{3})=75+\dfrac{35}{9}-\dfrac{36\sqrt{7}}{3}\\\\f(4-\dfrac{\sqrt{7}}{3})=\dfrac{675}{9}+\dfrac{35}{9}-12\sqrt{7}[/tex]

[tex]\boxed{\\\\f(4-\dfrac{\sqrt{7}}{3})=\dfrac{710}{9}-12\sqrt{7}}[/tex]