résoudre x^2 = 10x - 9 merci

Bonjour Boarward

[tex]x^2 = 10x - 9\\x^2-10x+9=0\\x^2-x-9x+9=0\\(x^2-x)-(9x-9)=0\\x(x-1)-9(x-1)=0\\(x-1)(x-9)=0\\x-1=0\ \ ou\ \ x-9=0\\\\\boxed{x=1\ \ ou\ \ x=9}[/tex]

[tex]x^2 = 10x + 9\\x^2-10x-9=0\\(x^2-10x+5^2)-5^2-9=0\\(x-5)^2-25-9=0\\(x-5)^2-34=0\\(x-5)^2-(\sqrt{34})^2=0\\(x-5-\sqrt{34})(x-5+\sqrt{34})=0\\x-5-\sqrt{34}=0\ \ ou\ \ x-5+\sqrt{34}=0\\\\\boxed{x=5+\sqrt{34}=0\ \ ou\ \ x=5-\sqrt{34}}[/tex]