A= 7/3(6a+3)-5/2(4-2a) B= (4b-1)(7+b)-(5+b)(-2+3b)
Mathématiques
Ari54
Question
A= 7/3(6a+3)-5/2(4-2a)
B= (4b-1)(7+b)-(5+b)(-2+3b)
B= (4b-1)(7+b)-(5+b)(-2+3b)
1 Réponse
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1. Réponse Eliott78
[tex]A = \frac{7}{3}(6a + 3) - \frac{5}{2}(4 - 2a) \\ \\ A = ( \frac{42}{3}a + \frac{21}{3}) - ( \frac{20}{2}- \frac{10}{2}a) \\ \\ A = (14a + 7) - (10 - 5a) \\ \\ A = 14a + 7 - 10 + 5a \\ \\ A = 19a - 3 \\ \\ \\ B = (4b - 1)(7+b) - (5 + b)(-2 + 3b) \\ \\ B = (28b + 4b^{2} - 7 - b) - (-10 + 15b - 2b - 3b^{2} ) \\ \\ B = 28b + 4 b^{2} - 7 - b + 10 - 15b + 2b - 3b^{2} \\ \\ B = +4b^{2} - 3b^{2} +28b -b - 15b + 2b -7+10 \\ \\ B = b^{2} + 14b + 3[/tex]