Mathématiques

Question

relatif_fractions
A=-5+(-7)-(-15)+(-10)+(+12)-5-(-3)
B=-3+(-4)+4-10-(-6)-(+3)-8

A=-5-3x(-10)
B=3+4x(-6)
C=5x(-10)-3
D=-6-(-5)x4

A=3-5x(-9)-5+6x7+(-5)x(-3)
B=9-(-7)x(-6)+12+(-8)x5+5
C=-4x(-3)-[-45:(27:-3)]

1 Réponse

  • A=-5+(-7)-(-15)+(-10)+(+12)-5-(-3)
    a = 5 -7 +15 -10 +12 -5+3
    a = 5+15+12+3 -7-10-5
    a = 35 -22
    a =13

    B=-3+(-4)+4-10-(-6)-(+3)-8
    b = -3-4+4-10+6-3-8
    b = -3-10+6-3-8
    b = -24+6
    b = -18

    A=-5-3x(-10)  = 5 +30 =35

    B=3+4x(-6) = 3 -24 = -21

    C=5x(-10)-3 -50-3 = -53

    D=-6-(-5)x4 = -6 +20 = 14

    A=3-5x(-9)-5+6x7+(-5)x(-3)
    a = 3 +45 -5 +42+15
    a =100

    B=9-(-7)x(-6)+12+(-8)x5+5
    b = 9 -42 +12 -40+5
    b =-70+14
    b = -56

    C=-4x(-3)-[-45:(27:-3)]
    c= +13 - (-45 : -9)
    c= 13 - (+5)
    c = 13-5
    c =8

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