Mathématiques

Question

calculer en détaillant et en donnant le résultat sous forme irréductible .
A=5/3-2/3÷ 6/5
B=2-3-1/3/3+1/3
C=(3+1/2)x7/3+1-2x1/7
D=3+1/7+1/15/1/1+1/292

1 Réponse

  • A = 5/3 - 2/3 ÷ 6/5
    A = 5/3 - 2/3 x 5/6
    A = 5/3 - 10/18
    A = 5 x 6 / 3 x 6 - 10/18
    A = 30/18 - 10/18
    A = 20/18
    A = 2 x 10 / 2 x 9
    A = 10/9

    B = 2 - 3 - 1/3 :3 + 1/3
    B = 2 - 3 - 1/3 x 1/3 + 1/3
    B = 2 - 3 - 1/9 + 1/3
    B = 2 x 9 / 1 x 9 - 3 x 9 / 1 x 9 - 1/9 + 1 x 3 / 3 x 3
    B = 18/9 - 27/9 - 1/9 + 3/9
    B = - 7/9

    C = (3 + 1/2) x 7/3 + 1 - 2 x 1/7
    C = (3 x 2 / 1 x 2 + 1/2) x 7/3 + 1 - 2/7
    C = (6/2 + 1/2) x 7/3 + 1 - 2/7
    C = 7/2 x 7/3 + 1 - 2/7
    C = 49/6 + 1 - 2/7
    C = 49 x 7 / 6 x 7 + 1 x 42 / 1 x 42 - 2 x 6 / 7 x 6
    C = 343/42 + 42/42 - 12/42
    C = 373/42

    D = 3 + 1/7 + 1/15 : 1/1 + 1/292
    D = 3 + 1/7 + 1/15 x 1/1 + 1/292
    D = 3 + 1/7 + 1/15 + 1/292
    D = 3 x 4380 / 1 x 4380 + 1 x 292 / 15 x 292 + 1 x 15 / 292 x 15
    D = 13140/4380 + 292/4380 + 15/4380
    D = 13447/380

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