resoudre l'equation: (4x-1) (2x+3)=3x (2-8x) ax+b=0 x²= π (2x- π)

1) 6x+12x-2x-3 = 6x-24x²
 6x+10x-3= 6x-24x²
 10x+24x²= 3
24x²+10x-3= 0
forme canonique: 24(x--5/24)²-97/24

2) ax+b=0
ax = -b
x = -b/a

3) x² = 2x-²
x =√2x-²